(1/3)^3x+4=7^x+3

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Solution for (1/3)^3x+4=7^x+3 equation: 



(1/3)^3x+4=7^x+3

We move all terms to the left:

(1/3)^3x+4-(7^x+3)=0



Domain of the equation: 3)^3x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^3x-(7^x+3)+4=0

We get rid of parentheses

(+1/3)^3x-7^x-3+4=0

We multiply all the terms by the denominator


(+1-7^x*3)^3x-3*3)^3x+4*3)^3x=0

Wy multiply elements

-27x^2+(+1-7^x*3)^3x=0

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